Question 195663
P(drawing a 4) = 1/7


once a 4 is drawn (and not put back), there are 6 cards left. So 


P(drawing a 6 next) = 1/6


So ...


P(drawing a 4 then a 6) = P(drawing a 4) * P(drawing a 6 next) = (1/7)*(1/6) = (1*1)/(7*6) = 1/42