Question 195207
Let n = no. of nickels; let d = no. of dimes
:
Tommy has dimes and nickles. He has 12 more nickles than dimes.
n = d + 12
:
The total is $1.65.
.05n + .10d = 1.65
:
How many of each does he have.
:
Substitute (d+12) for n in the above equation:
.05(d+12) + .10d = 1.65
:
.05d + .6 + .1d = 1.65
:
.05d + .1d = 1.65 - .6
:
.15d = 1.05
d = {{{1.05/.15}}}
d = 7 dimes
then
n = 7 + 12
n = 19 nickels
:
:
Check solution
.05(19) + .10(7) =
.95 + .70 = 1.65; confirms our solutions