<PRE><B>Question 195471</B>
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First substitute -1 for &lt;b&gt;&lt;i&gt;x&lt;/i&gt;&lt;/b&gt; in


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5x^2 - 5x - 5]


and do the arithmetic to calculate the value of &lt;b&gt;&lt;i&gt;a&lt;/i&gt;&lt;/b&gt;.


Then, using that value of &lt;b&gt;&lt;i&gt;a&lt;/i&gt;&lt;/b&gt;, substitute into


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5a - 5] and do the arithmetic.




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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