Question 195441
{{{x^2+18=9x}}}
Move all the x's to the left:
{{{x^2-9x+18=0}}}
{{{x^2-9x= -18}}}
Add to both sides half b coefficient then square it:
{{{x^2-9x+(81/4)= -18 + (81/4)}}}
{{{(x-(9/2))^2= -(72/4) + (81/4)}}}
{{{(x-(9/2))^2= (9/4)}}}
Taking the square root of both sides:
{{{x-(9/2)= 3/2}}}
{{{x = 3/2 + (9/2)}}}
{{{x = 12/2}}}
{{{x = 6}}}