Question 195267
first u must plug the Logarithm back into exponential form... which is b^x=y (if u dont know the equation for the log it is log b^y=x) 
that would then make the equation X^27=5 
the you would take the 27 root of 5 and that with give you x 
which should equal 1.06142125 which rounded is 1.1