Question 195283
Distance(d) equals Rate(r) times Time(t) or d=rt;  r=d/t and t=d/r
Let r=speed of plane in still air
And let w=windspeed
(With the wind, we add windspeed, against, we subtract)
r+w=520/(3 1/3)=520/(10/3)=1560/10=156 mph-----eq1
r-w=460/(3 1/3)=460/(10/3)=1380/10=138 mph---eq2
  add eq1 and eq2

2r=294
r=147 mph-------------speed of plane in still air
substitute into eq1
147+w=156
w=156-147=9 mph ------speed of wind
CK
520/156=3 1/3 hr
460/138=3 1/3 hr

Hope this helps---ptaylor