<PRE><B>Question 195304</B>
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Let &lt;b&gt;&lt;i&gt;x&lt;/i&gt;&lt;/b&gt; represent the smaller integer.  The next consecutive integer is then &lt;b&gt;&lt;i&gt;x&lt;/i&gt; + 1&lt;/b&gt;.  Twice the larger is then *[tex \LARGE 2(x + 1) = 2x + 2], so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x + 2x + 2 = 29]


Solve for x



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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