Question 195254
A 30% solution of barium chloride is mixed with 10 L of water to form a 20% solution. How many liters of original solution did we start with?
.
Let x = amount 30% solution of barium (liters of original solution)
then
.30x = .20(10+x)
.30x = 2 + .20x
.10x = 2
x = 2/.10
x = 20 Liters