Question 195253
A quadrilateral has 4 sides as suggested in the name (quad). Add up the 4 sides given in the question.

(x+2) + (2x+1) + (x-5) + (x^2-3x)

It is given in the question that the perimeter is 130 inches. Hence:

(x+2) + (2x+1) + (x-5) + (x^2-3x) = 130 

Simplify the equation:

x^2 - x - 2 = 130

x^2 - x - 132 = 0 

By factorisation:

(x - 12)( x + 11)= 0

Therefore x = 12          or        x = - 11 (reject since x cannot be negative)

Substitute x = 12 into the 4 sides given: 

x + 2 = 12 + 2            = 14 
2x + 1 = 2(12) + 1        = 25
x - 5 = 12 - 5            = 7
x^2 - 3x = (12)^2 - 3(12) = 108

Hence, the 4 sides of the quadrilateral are 14 inches, 25 inches , 7 inches and 108 inches.