Question 195250
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If 6 workers can complete 9 jobs in 3 days, then


6 workers can complete 9/3 = 3 jobs in 3/3 = 1 day, then


6/6 = 1 worker can complete 3/6 = 1/2 job in 1 day, then 


4 * 1 = 4 workers can complete 4 * 1/2 = 2 jobs in 1 day, then


4 workers can complete 5 * 2 = 10 jobs in 5 * 1 = 5 days.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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