Question 195219
what is logx + log (x-0.21) = -2?
log[x(x-0.21)) = -2
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x(x-0.21) = 10^-2
x^2 - 0.21x - 0.01 = 0
(x + 0.04)(x - 0.25) = 0
Positive solution:
x = 0.25
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Cheers,
Stan H.