Question 195142
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Let <b><i>x</i></b> represent the width, then <b><i>x</i> + 3</b> represents the length, in other words the two legs of the right triangle formed by the diagonal.


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2 + (x + 3)^2 = 20^2]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2 + x^2 + 6x + 9 = 400]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x^2 + 6x - 391 = 0]


Solve the quadratic using the quadratic formula.  Discard the negative root because we are looking for a positive measure of length.  The positive root will be the width.  Add 3 to get the length.  Remember to round to 2 places.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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