Question 195076
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Solve by Quadratic:
{{{x^2+x-10=0}}}
Solving discriminant: {{{b^2-4ac=1^2-4*1*-10=1+40=41}}}
Then,
{{{x=(-1+-sqrt(41))/(2*1)=(-1+-6.4)/2}}}
{{{x=(-1+6.4)/2=5.4/2=red(2.7)}}}
{{{x=(-1-6.4)/2=-7.4/2=-3.7}}}, disregard


Since, x=2.7, rounding off equals <font color=blue>x=3</font> employees
(should be greater than 2.7 anyway)


Check by susbtituting:
{{{P=3^3+3-10}}}
{{{P=9-7}}}
{{{red(P=2)}}}, "+", oks!


If we use x=2.7, then P=0.
If you see the graph,
{{{drawing(400,400,-10,10,-10,10,graph(400,400,-10,10,-10,10,x^2+x-10),green(line(3,0,3,2)),green(circle(3,2,.15)),green(locate(4,2,Profit=plus)),green(locate(4,-1.5,Employees)))}}}


Thank you,
Jojo</font>