<PRE><B>Question 195046</B>
Lets  view  this  as  a  right  triangle  problem
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The  hypotenuse  is  30,  the  length  of  the  rope
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one  leg  is  b,,,,the  unknown  base
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the  other  leg  is  (b+6),,,unknown  height,  but  related  to  base
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Using  pythagouous,  c^2 = a^2 + b^2
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30 ^2 = b^2 + (b+6)^2
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900  = b^2 + ( b^2 +12b +36)
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0 = 2 b^2 +12b -864
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0 = (2) (b^2 +6b -432)
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0 = 2 ( b+24) (b-18)
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b = 18, or  -24 ( not  realistic)
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Therefore  base  is  18,  height  is  24 (18+6)
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checking
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30^2 = 18^2 +(18+6)^2 = 18^2 + 24^2 = 900,,,,ok</PRE>