Question 194985
Help I am so confused. 
1) 2x^2=6 what are the solutions x=
what are the x intercepts 
The x-intercepts are the solutions.
2x^2 = 6
x^2 = 3
x = ± sqrt(3)
*[invoke solve_quadratic_equation 1,0,-3]
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Ignore the factoring statement.
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2) 10T^2-8T = 0 What is the nature of the solution 
It's a parabola with the vertex (maximum) at the top (assuming T is horizontal).
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3) what is the vertex of f(x)=-x^2+12x+3 
The vertex is at x = -b/2a
or x = -12/(12) = 6
At x = 6, f(x) = -36 + 72 + 3 = 39
--> (-6,39)