Question 194979
please help me with factoring? 
4s^3+12s^2-64s-192
Factor the 1st two and the last two terms separately to get:
= 4s^2(s+3) - 64(s + 3)
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= (s+3)(4s^2- 64)
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= 4(s+3)(s^2 - 16)
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= 4(s+3)(s-4)(s+4)
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Cheers,
Stan H.