<PRE><B>Question 194973</B>
How would you us e the quadratic equation to answer:
4z^2+z-6=0
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ForM x = [-b +- sqrt(b^2 - 4ac)]/(2a)
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Your Problem:
a = 4 ; b = 1 ; c = -6
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z = [-1 +- sqrt(1 -4*4*-6)]/(2*4)
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z = [-1 +- sqrt(1+ 96)]/8
z = [-1 +- sqrt(97)]/8
z = [-1 + sqrt(97)]/8 or z = [-1 - sqrt(97)]/8
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Cheers,
Stan H.

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