Question 194893
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Depends.  Did you mean:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{\sqrt{7}y} = \left(\frac{1}{\sqrt{7}y}\right)\left(\frac{\sqrt{7}}{\sqrt{7}}\right)=\frac{\sqrt{7}}{7y}]


or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{\sqrt{7y}} = \left(\frac{1}{\sqrt{7y}}\right)\left(\frac{\sqrt{7y}}{\sqrt{7y}}\right)=\frac{\sqrt{7y}}{7y}]


?




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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