Question 194888
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2 + 4x + 4 = 0]


Since 2 + 2 = 4 and 2 X 2 = 4, the left had expression is a perfect square trinomial:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x + 2)(x + 2) = 0]


Using the Zero Product Rule


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x + 2 = 0 \ \ \Rightarrow\ \ x = -2]


or


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x + 2 = 0 \ \ \Rightarrow\ \ x = -2]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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