Question 194802
1.{{{sqrt(x)-5=7}}}
sqrt(x) = 12
Square both sides to get:
x = 144
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2.{{{sqrt(3x)/sqrt(2x+3)=2}}}
Square both sides to get:
3x/(2x+3) = 4
3x = 8x + 12
5x = -12
x = -12/5
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3.{{{sqrt(x+5)=x+3}}}
Square both sides to get:
x+5 = x^2 + 6x + 9
x^2 + 5x + 4 = 0
(x+4)(x+1) = 0
x = -4 is extraneous as it doesn't work in the original equation.
x = -1 is the only solution
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Cheers,
Stan H.