Question 194761
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Please use parentheses in the future so that we don't have to guess at what you meant.  I presume you meant:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\sqrt{6}}{4\sqrt{3}+\sqrt{2}}]


Multiply by 1 in the form of the conjugate of the denominator divided by itself:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \left(\frac{\sqrt{6}}{4\sqrt{3}+\sqrt{2}}\right)\left(\frac{4\sqrt{3}-\sqrt{2}}{4\sqrt{3}-\sqrt{2}}\right) = \frac{24\sqr{3}-6\sqrt{2}}{48 - 2} = \frac{12\sqrt{3} - 3\sqrt{2}}{23}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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