Question 194725
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_2{(3x+1)}=3]


Remember that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_b{x} = y \ \ \Rightarrow\ \ b^y = x]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x + 1 = 2^3 = 8]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x = 7]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x = \frac{7}{3}]




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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