Question 194661
What is the vertical asymptote for the function {{{ y=(x^2-49)/(x^2+8x+16) }}}?
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Examine the denominator.
x^2+8x+16 = (x+4)^2
The denominator will be zero when x = -4
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Therefore the function has a vertical asymptote at x = -4
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Cheers,
Stan H.