Question 194646
A TV station airs a movie of the day every tuesday and thursday. Their research shows that their suspense movies are viewed on average by 3500, comedies by 4500, dramas by 6000. They decided to buy 100 movies consisting of 15 suspense, 40 comedies, 45 dramas. The movies will be shown two per week for 50 weeks. Find the expected number of viewers on a given movie. 
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Random number values for # of viewers: 3500, 4500, 6000
Associated probabilities are (3500/14000), (4500/14000), (6000/14000)
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Expected value of the random variable is:
3500(3500/14000) +  4500*(4500/14000) + 6000(6000/14000) 
= 875 + 1446.43 + 2571.43
= 4892.86
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Cheers,
Stan H.