Question 194642
if  we  use  the  form,, y = C(1 + r)^t,,  for  exponential  growth,,this  makes  sense,
as  t  grows,  y  also  grows but  at  exponential  rate. If  r=.2,  as  t  grows 1,  y  grows 1.2 C,
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if  we  look  at  the  form ,  y=C(1-r)^t,,,for  exponential  decay,
as  t  grows,  y  decays  at  an  exponential  rate.  If  r=.2,  as  t  grows 1,  y  decays  to  .8C.
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to  remember  this  think  of  it  as  the  discount vs  tax increase.
we  use (1+r)  for  taxes (increases),,,,and  (1-r) for  discounts.
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Good  Question,,,,keep  up  good  work