Question 194638
The product of two consecutive integers is 3 less than 3 times their sum. Find the integers
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1st: x
2nd: x+1
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Equation:
x(x+1) = 3(x+x+1)-3
x^2+x = 6x
x^2-5x = 0
Factor:
x(x-5) = 0
x = 0 or x = 5
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If x = 0 , x+1 = 1
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If x = 5, x+1 = 6
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Cheers,
Stan H.