Question 194629
sqrt2 / (  2sqrt6-sqrt2)
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usually  we  clear  the  den  of  radicals  by  multiplying  thru  by  complex  conjugate
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( sqrt2 * (2 sqrt6 + sqrt2) )  /  ( 2sqrt6 -sqrt2) * (2sqrt6 + sqrt2)
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(2 sqrt2 *sqrt6 + sqrt2 * sqrt2 )  /  ( 4*6 -2 ) 
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(2sqrt12 +2)/ 22
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( sqrt 12 +1) / 11,,,,ANSWER
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checking
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evaluate  original  and  answer  with  calculator,  both  give  .406,,,,ok