<PRE><B>Question 26833</B>
You solve this problem by making two tables:
The first table is for the groups of four with two leftover.

3 X 4 + 2 = 14
4 X 4 + 2 = 18
5 X 4 + 2 = 22
6 X 4 + 2 = 26

The second table is for groups of five with one leftover.

2 X 5 + 1 = 11
3 X 5 + 1 = 16
4 X 5 + 1 = 21
5 X 5 + 1 = 26

The last entries in the two tables show that Mary must have had at least 26 dimes.
She could make 6 groups of 4 dimes with 2 leftover or she could make 5 groups of 5 dimes with 1 leftover. 

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