Question 194552
log(3) 64 -log(3) 8/3 + log(3) 2 = log(3) 4R
log (3) [  { 64 *2} / (8/3)  ]  =  log (3)  4R
log(3)  (48)  =  log(3)  4R
48  =  4 R
R = 12,,,,,,,,ANSWER
,
checking
log 64/log3 -log(8/3)/log3 +log2//og3  =  log  48/log 3
1.68  =  1.68  ,,,,,,ok