Question 194543
For the given area, find the length and width of the rectangle with the least perimeter. Use whole numbers only. 
30 m2
40 yd2
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A square has the least perimeter for a rectangle. (A proof is available is needed.)
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For squares, P = 4*s
30 sq meters --> sides of sqrt(30) meters
l = w = sqrt(30) = ~ 5.477 meters
Using integers, --> 5 by 6.
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40 sq yds --> sqrt(40)
l = w = sqrt(40) = ~ 6.325 yards
Using integers --> 5 by 8 yards
This is a silly problem.