Question 194519
x = 2y^2 +4y +5
,
Leading  coefficient  is  positive  therefore  it  opens  to  right
,
y  vertex  is  at  -b/2a,,, -(4)/2(2) = (-1)
x  vertex  is  found  by  substituting,  x= 2(-1)^2 +4(-1) +5 = +3
Vertex  is  (3,-1)
axis  of  symmetry  is  y= -1
,
checking  by  plotting  a  few  points,,,(3,-1),,,(5,0),,,,(5,-2),,,,ok