Question 194509
tan^2a -sin^2a  = sin^2a * tan^2a,,,,let  a  =  theta
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but  tan =  sin /  cos
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sin^2 a/cos^2a -sin^2a = sin^2a *tan^2a
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remember  cos^2 = sin^2 =1,,,  cos^2a = 1=sin^2a
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sin^2a / ( 1-sin^2a)  - sin^2a = sin^2a * tan^2a
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using  lcd = (1-sin^2a)
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( sin^2a -sin^2a (1-sin^2a) )/ (1-sin^2a) = sin^2a *tan^2a
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(  sin^2a -sin^2a +sin4a ) (1-sin^2a) = sin^2a * tan^2a
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but  cos^2a = 1 - sin^2a
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 sin^4a / cos^2a  =  sin^2a * tan^2a
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 with  tan =  sin / cos
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sin^2a * tan^2a = sin^2a * tan^2a