<PRE><B>Question 194385</B>
In one city, the population P grows at the rate of 2% per year. The equation P= 1,000,000 (1.02)^t gives the population t after 1998. Find the value of t for which the population is 1,500,000.
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P(t) = 1,000,000(1.02)^t
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1,000,000(1.02)^t = 1,500,000
1.02^t = 1.5
Take the log
tlog1.02 = log1.5
t = log1.5/log1.02
t = 20.48 years.
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Cheers,
Stan H.</PRE>