Question 194280
Solve for x:
{{{125^((x-2)) = 25^((3x+1))}}} Substitute {{{125 = 5^3}}} and {{{25 =5^2}}}
{{{(5^(3))^((x-2)) = (5^2)^((3x+1))}}} Simplify.
{{{5^((3x-6)) = 5^((6x+2))}}} The bases (5) are equal so the exponents are equal.
{{{3x-6 = 6x+2}}} Subtract 3x from both sides.
{{{-6 = 3x+2}}} Subtract 2 from both sides.
{{{-8 = 3x}}} Divide both sides by 3.
{{{x = -8/3}}}
Solution: 
x = -2 2/3