Question 194312
You are correct!
{{{3x^3-48x = 0}}} Factor out 3x.
{{{3x(x^2-16) = 0}}} Apply the zero product rule:
{{{3x = 0}}} or {{{x^2-16 = 0}}}
{{{3x = 0}}} so {{{highlight(x = 0)}}} and...
{{{x^2 = 16}}} so {{{highlight(x = 4)}}} or {{{highlight(x = -4)}}}