Question 194220
    logx (2x + 5) = 2
    (2x + 5) = x^2
    0 = x^2 - 2x - 5
.
Solving with the quadratic equation yields:
x = {3.449, -1.449}
We can toss out the negative solution leaving:
x = 3.449
.
Details of quadratic follows:
.
*[invoke quadratic "x", 1, -2, -5 ]