Question 194179
4x^2 + 16x +16 =0
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4 (x^2 + 4x + 4) =0
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check  Discriminant,  remember,  D less  than  0,  no  solutions
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,D  =0,,,,,one  solution
,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,D > 0,,,,,two  solutions
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a=1,,b=4,,,c=4,,,,and  D = sqrt ( b^2 - 4 * a * c ) = sqrt ( 16 -4 * 1 * 4 ) =0
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therefore  one  solution
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factoring ( x^2 +4x +4 ) = (x+2) (x+2 ),,, x=-2,,and  -2,,
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this  is  a  duplicate  solution  and  counts  as  1  (one)  solution
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The  function  is  a  positive  parabola,  cup  pointed  up,  with  vertex  just  touching  y  axis,  at  x=-2