Question 193914
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The equation of a circle with center at <b>(<i>h, k</i>)</b> is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x - h)^2 + (y - k)^2 = r^2]


So, for your first problem, the center is at (2, 3) and the radius is *[tex \LARGE \sqrt{16} = 4]


Do the rest of them the same way.


<b>Hint:</b> *[tex \LARGE x^2 = (x - 0)^2]


<b>Hint:</b> if *[tex \LARGE r^2] is not a perfect square, leave the answer in radical form.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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