Question 194135
Let {{{p}}}= perimeter, and the sides be
{{{a}}},{{{b}}}, and {{{c}}}
{{{p = a + b + c}}}
Let {{{b}}} = {{{a + 2}}}
Let {{{c = a + 4}}}
Given:
{{{75 = a + b + c}}}
{{{75 = a + a + 2 + a + 4}}}
{{{75 = 3a + 6}}}
{{{3a = 69}}}
{{{a = 23}}}
{{{a + 2 = 25}}}
{{{a + 4 = 27}}}
The sides of the triangle are 23,25, and 27
check:
{{{p = a + b + c}}}
{{{75 = 23 + 25 + 27}}}
{{{75 = 75}}}
OK