Question 194042
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ( x + a )( x + b )= x^2 + ( b - 6)x + 180]


Using FOIL we know that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ( x + a )( x + b ) = x^2 + (a + b)x + ab]


From which we can see that:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ ab = 180]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a + b = b - 6]


So,


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a = -6]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ b = \frac{180}{-6} = -30]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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