Question 193927
The volume of a right circular cone is:
{{{V = (1/3)Bh}}} where B = the area of the base ({{{pi*r^2}}}) and h is the height of the cone.
In this problem, the diameter of the base is 6 ft. so its radius (r) is 3 ft.
The height (h) is given as 10 ft.
{{{V = (1/3)(pi*r^2)*h}}} Make the appropriate substitutions and use {{{pi = 3.14}}} as an approximation.
{{{V = (1/3)(3.14)(3^2)(10)}}}
{{{V = 94.2}}}cu.ft. Now multiply this by {{{7.480519}}}gallons/cu.ft.
Answer: 704.67 gallons (rounded to nearest hundredth)