Question 193830
<font size = 9 color = "red"><b>Edwin's solution:
I think you meant "initial velocity 55 ft/sec"!

<font size = 4 color = "indigo">

The formula is

{{{h = h[0] + v[0]t - 16t^2}}}

Where 

{{{h[0]}}} is the initial height 2 ft 
{{{v[0]}}} is the initial velocity 55 ft/sec
{{{t}}} is the time you "freeze" the ball 2 seconds.

{{{h = h[0] + v[0]t - 16t^2}}}
{{{h = 2 + 55(2) - 16(2)^2}}}

{{{h = 48}}}ft.

Edwin</pre>