Question 193821
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^3 - 2x^2 + 9x - 18]


Put the terms into two groups (hence the name, factor by <i>grouping</i>)


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x^3 - 2x^2) + (9x - 18)]


Factor an *[tex \LARGE x^2] out of the first group, and a 9 out of the second group:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2(x - 2) + 9(x - 2)]


Now notice that each term has a factor of <b>(<i>x</i> - 2)</b>


Factor that out:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (x^2 + 9)(x - 2)]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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