Question 193748
Is this the area for a triangle? If so, then...



{{{A=(bh)/2}}} Start with the area of a triangle formula



{{{88=(11*sqrt(3x-2))/2}}} Plug in the given values



{{{88(2)=11*sqrt(3x-2)}}} Multiply both sides by 2



{{{176=11*sqrt(3x-2)}}} Multiply



{{{176/11=sqrt(3x-2)}}} Divide both sides by 11



{{{16=sqrt(3x-2)}}} Divide



{{{16^2=3x-2}}} Square both sides



{{{256=3x-2}}} Square 16 to get 256



{{{256+2=3x}}} Add 2 to both sides



{{{258=3x}}} Add



{{{258/3=x}}} Divide both sides by 3



{{{86=x}}} Reduce



So the solution is {{{x=86}}}