Question 193718
5v1024x^4y^22
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5th rt(1024x^4y^22)
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= (1024x^4y^22)^(1/5)
= (2^10*x*4*y^22)^(1/5)
= [(2^10*y^20)^(1/5)]*[x^4*y]^(1/5)]
= (2^2*y^4)* (x^4y)^(1/5)
= (4y^4)*(x^4*y)^(1/5)



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Cheers,
Stan H.