Question 193726
we  believe  the  problem  is:
,
z^2/(z-3)  - z/(z+3)
,
LCD  is  (z-3)(z+3)
,
(  z^2(z+3) - z(z-3)  ) / ( (z+3) (z-3) )
,
( z^3+3z^2-z^2+3 ) / (z+3)(z-3)
,
( z^3 + 2z^2 +3 ) / ( (z+3)(z-3)  )
,
checking,,
let  z=0,  original  =0,  answer  =0
let  z=1,  original  =-3/4,,,answer  =  -6/8==-3/4,,,ok