Question 26742
Lets look at the "human" way of doing this:


All possible combinations are:
H1
H2
H3
H4
H5
H6
T1
T2
T3
T4
T5
T6


--> 12 possible outcomes and you want the probability of H4, which is 1 of these...so P(H4) = 1/12


Mathematically,
P(H and 4) = P(H) AND P(4) --> AND meaning multiplication
P(H and 4) = 1/2 x 1/6
P(H and 4) = 1/12


jon.