Question 193704
remember  three  ways  to  solve  linear  equations,  1)  graph,  2) substitution,  3)elimination
on  this  one  let's  try  elimination
,
1)  2x+3y=21
2)  x/2+y/3=19/6
,
to  eliminate  fractions  let's  multiply  (2)  by  6
,
2a)  3x  +2y  =19
,
Comparing  1)  and  2a),  we  might  multiply,  1) by  3,,and  2a)  by  2,, to  get  common  coefficients
'
1)    6x  +9y =63
2a)  6x  +4y =38
,
Now  let's  subtract  1)-2a)
,
5y=25
y=5,,,,,ANSWER
,
substitute  into  1)
,
2x+3(5)=21
2x=21-15=6
x=3,,,,,,ANSWER
,
checking
1)  2(3)+3(5)=21
6+15=21,,,ok
2)  (3)/2  +(5)3 = 19/6
1.5+1.667=3.167
3.167=3.167  ,,,ok