Question 193652
    log4(x)+log4(x-6)=2
    log4((x)(x-6))=2
    (x)(x-6)=4^2
    (x)(x-6)=16
    x^2-6x=16
    x^2-6x-16=0
    (x-8)(x+2) = 0
.
x = {-2, 8}
Throw out the negative solution (can't have log of negatives):
x = 8