Question 193653
log(x+1)+log(x-2)=1
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log((x+1)*(x-2)) = 1
(x+1)*(x-2) = 10
{{{x^2 - x - 2 = 10}}}
{{{x^2 - x - 12 = 0}}}
(x-4)*(x+3) = 0
x = 4
x = -3